python - Adding a Random Item to a List for a Text-Based RPG -

this concatenated question asked earlier today ("list" object not callable, syntax error text-based rpg). dilemma resides in adding herb player's herb list.

self.herb = [] 

is starting herb list. function collectplants:

def collectplants(self):     if self.state == 'normal':     print"%s spends hour looking medicinal plants." % self.name         if random.choice([0,1]):         foundherb = random.choice(herb_dict)         print "you find %s." % foundherb[0]         self.herb.append(foundherb)         print foundherb     else: print"%s doesn't find useful." % self.name 

with foundherb being random choice. how add item list in neat way (currently prints herb name, "none") , allow having several of same herb?

here's herb class:

class herb:     def __init__(self, name, effect):         self.name = name         self.effect = effect 

sample list of herbs (warning: immaturity):

herb_dict = [     ("aloe vera", player().health = player().health + 2),     ("cannabis", player().state = 'high'),     ("ergot", player().state = 'tripping') ] 

use list.

self.herb = [] foundherb = 'something' self.herb.append(foundherb) self.herb.append('another thing') self.herb.append('more stuff')  print 'you have: ' + ', '.join(self.herb) # have: something, thing, more stuff 

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edit: found code foundherb in 1 of other questions (please post in question too!), is:

foundherb = random.choice(herb_dict) 

when @ herb_dict:

herb_dict = [     ("aloe vera", player().health == player().health + 2),     ("cannabis", player().state == 'high'),     ("ergot", player().state == 'tripping') ] 

1. this wrong, use = assignment. == testing equality.
2. you need use function in second item in these tuples.

3. don't add second item list. this:

   self.herb.append(foundherb[0])