PHP Load content (picture) of URL from another URL (json) -

im trying this: load http://example.com/nickname/picture (nickname loaded var in url visit, that´s working) decode json site this

{ "picture": "https://example.com/hf8329yrh8oq.jpg" } 

load picture tried:

function curlget($url)    {    $crl = curl_init();    $timeout = 5;    curl_setopt ($crl, curlopt_url,$url);    curl_setopt ($crl, curlopt_returntransfer, 1);    curl_setopt ($crl, curlopt_connecttimeout, $timeout);    $status = curl_exec($crl);    curl_close($crl);    return $status;    } $profpiccurl = curlget('https://example.com/'.urlencode($_get['nickname']).'/picture') $profpic = json_decode($profpiccurl,true); echo file_get_contents($profpic.["picture"]); 

i know didn´t handle errors , stuff in script, want work real image first before.

so mean question: how display , image decoded json site?

do need curl?
can replace file_get_contents curlget in code

<?php   $profpic  = json_decode( file_get_contents( 'https://example.com/'.urlencode( $_get['nickname'] ).'/picture' ) );   if ( $profpic ) { // valid json object     if ( isset( $profpic->picture ) ) { // profile picture exists       $profpic  = $profpic->picture;       $extension  = strtolower( pathinfo( $profpic, pathinfo_extension ) ); // image extension       $content  = file_get_contents( $profpic ); // content of image       if ( $content ) {         header( "content-type: image/".$extension ); // set mime type         echo $content; // output content         exit();       }     }   }   echo "file not found"; // there errors :\ ?>