unix - error handling in shell scripting with typeset -

i trying catch typeset error below shell script test.sh:

shell script

typeset -i int int=2 echo $int int=asd || echo "type mismatch" 

but getting output as:

output

./test.sh 2 ./test.sh[4]: asd: bad number 

required result

./test.sh 2 ./test.sh[4]: asd: bad number **type mismatch** 

i using following machine:

bash --version gnu bash, version 3.2.51(1)-release (sparc-sun-solaris2.10) copyright (c) 2007 free software foundation, inc. 

please suggest me change need make in script. need way make sure input parameter int. , have use typeset along exception handling.

try using eval:

typeset -i int   # using name "int" seems asking trouble! eval int="$1" || echo "type mismatch" >&2 

the issue in line int=asd || ..., first simple command evaluate true required standard, since no command given. variable assignments take place in current shell, no command given , results specified in section 2.9.1 :

if there command name, execution shall continue described in command search , execution . if there no command name, command contained command substitution, command shall complete exit status of last command substitution performed. otherwise, command shall complete 0 exit status.