i have vector of integers let's 1 3 (can more):
x <- sample(1:3, 10, replace=t) [1] 1 3 1 2 2 1 3 2 3 2 if sort x i'll get
sort(x) [1] 1 1 1 2 2 2 2 3 3 3 but need 2s go first, 1s, 3s.
[1] 2 2 2 2 1 1 1 3 3 3 so, if have vector y = c(2, 1, 3), how can use sorting order?
and need not values itself, index of sorted values in original vector, order function.
a simple remapping of values works:
x <- sample(1:3, 10, replace=t) x [1] 2 3 1 1 3 2 2 3 3 2 order(c(2,1,3)[x]) [1] 1 6 7 10 3 4 2 5 8 9
Comments
Post a Comment